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Configuration = 15
cycles = (10 3 1 6 2)(9 7 4 8 5)

a = 1, b = 4, c = 8
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cycles = (10 7 5 2 9 4 1 3 6)(8)

a = 4, b = 6, c = 10
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cycles = (10)(9 2 7 8 5)(6)(4 1 3)

a = 1, b = 3, c = 4
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cycles = (10)(9 3 7 8 5)(6)(4)(2)(1)

a = 3, b = 7, c = 9
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cycles = (10)(9 4 7)(8)(6)(5)(3)(2)(1)